 along the curve C which is the straight line from the origin
to the point (1,1).  One way to describe the curve C is to say it is the 
graph of the equation y = x as x ranges from 0 to 1.  So we can 
parameterize the line as x = t, y = t,
  along the curve C which is the straight line from the origin
to the point (1,1).  One way to describe the curve C is to say it is the 
graph of the equation y = x as x ranges from 0 to 1.  So we can 
parameterize the line as x = t, y = t,   .  Then, we see that,
along C, the vector field is
 .  Then, we see that,
along C, the vector field is   , so
 , so
  
 
 and
  and   where
 
where   is the line segement from the origin to (1,0) and
  is the line segement from the origin to (1,0) and   is
the line segment from (1,0) to (1,1).  Along
  is
the line segment from (1,0) to (1,1).  Along   we have
  we have   so that
  so that   .  Along
 .  Along   we have
  we have
  so that .  The line 
integral is then
  so that .  The line 
integral is then
  
 
Notice that this is the same answer as in the previous example, even though we used a different path of integration. This happened because the vector field is a speacial type of vector field. The entire next chapter will be devoted to studying the interesting properties of these fields, called conservative vector fields. To see that this doesn't always work, try the integrating the vector field over the same two paths.
 .  Compute the line integral of this vector field
along the path
 .  Compute the line integral of this vector field
along the path   between the points (1,1) and (2,4).  The proper
parameterization of the path is
  between the points (1,1) and (2,4).  The proper
parameterization of the path is   .  Then,
 .  Then,
  with
  with   .
 .
 