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Independence of Parameterization

From the previous chapter on parameterization, you should remember that there are many ways to parameterize a path. Since parameterization is crucial to the concept of evaluating a line integral, what effect does this have? Let's find out.

Suppose we have a vector field tex2html_wrap_inline498 where tex2html_wrap_inline332 is the parameterization of the curve C, with parameter t. Now make a change of parameterization. In other words, let's suppose that there is another way to parameterize the curve using s and that tex2html_wrap_inline508 . Also, let's let the interval tex2html_wrap_inline510 correspond to the interval tex2html_wrap_inline314 . The new parameterization, tex2html_wrap_inline514 , so the chain rule gives us tex2html_wrap_inline516 and

eqnarray197

Thus, we see that changing the parameterization had no effect at all on the line integral! This property is referred to as independence of parameterization. Notice that the curve traced out in the new parameter is the same as the curve in the old parameter. The only thing that realy changed was how we traced out the curve. In general, if we were to change the path into a new curve, we would get a completely different answer.



Vector Calculus
Sun Jul 27 11:36:39 MST 1997