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Tests for Conservative Vector Fields

The graphical test is not very accurate. It is almost impossible to tell if a three dimensional vector field is conservative in this fashion. We can use this idea to develop an analytical approach to testing whether a vector field is conservative or not. Recall that the curl is a way to measure a vector field's tendency to swirl. Thus, to eliminate the swirling, we want

\begin{displaymath}
\vec{\nabla} \times \vec{F} = \vec{0}\end{displaymath} (2)

in order to ensure that $\vec{F}$ is a conservative vector field.

Let's check this condition for the vector fields in the example above.

\begin{displaymath}
\vec{F}(x,y) = \frac{x}{x^2 + y^2} \hat{i} + \frac{y}{x^2 + ...
 ...
\qquad \qquad \vec{G}(x,y) = -y \hat{i} + x\hat{j} + 0\hat{k}.\end{displaymath} (3)

\begin{displaymath}
\vec{\nabla} \times \vec{F} = \left\vert \begin{array}
{ccc}...
 ...{2xy}{(x^2 y^2)^2} +
\frac{2xy}{(x^2 + y^2)^2}\right) = \vec{0}\end{displaymath} (4)

\begin{displaymath}
\vec{\nabla} \times \vec{G} = \left\vert \begin{array}
{ccc}...
 ...y & x & 0 \end{array} \right\vert = \hat{k}(1 -
-1) = 2 \hat{k}\end{displaymath} (5)


Vector Calculus
12/6/1997