next up previous
Next: The Order of Integration Up: Integration Over Non-Rectangular Regions Previous: The Key to getting

An example

A circular island named GUE has a population of carnivorous groo living on it. The island has a radius of 5 km, and if we place the origin of a coordinate system at the center of the island, the population density of groo is given by the function $g(x,y) = \frac{1}{\pi}(25 - xy)$. What is the total number of groo on the island?

To find this, we must integrate g(x,y) over the region, R, shown below.



Note that the endpoints of the lines shown give the equations of the boundaries. (Recall that the equation of a circle of radius 5 centered at the origin is x2 + y2 = 25.) If we integrate bottom to top then left to right (ie. y then x) we have the boundaries:


Boundary Equation
left x = -5
right x = 5
bottom $y = -\sqrt{25 - x^2}$
top $y = \sqrt{25 - x^2}$

Thus, the total population of groo is

\begin{displaymath}
\int_R gdA = \int_{-5}^5 \left( \int_{-\sqrt{25 - x^2}}^{\sqrt{25 -
x^2}} \frac{1}{\pi}(25 - xy) dy \right) dx \end{displaymath}

\begin{displaymath}
= \frac{1}{\pi} \int_{-5}^5 \left[ 25y - \frac{1}{2}xy^2
\right]_{-\sqrt{25-x^2}}^{\sqrt{25-x^2}} dx \end{displaymath}

\begin{displaymath}
= \frac{1}{\pi} \int_{-5}^5 50\sqrt{25 - x^2} dx = 625 \quad
\mbox{groo}.\end{displaymath}


next up previous
Next: The Order of Integration Up: Integration Over Non-Rectangular Regions Previous: The Key to getting
Vector Calculus
8/20/1998